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Re: st: Loop to replace values of a variable
From
Nick Cox <[email protected]>
To
"[email protected]" <[email protected]>
Subject
Re: st: Loop to replace values of a variable
Date
Wed, 18 Dec 2013 13:38:26 +0000
No loop needed; or rather, Stata will willingly loop on your behalf.
replace x = n / 10
Nick
[email protected]
On 18 December 2013 13:33, emanuele mazzini <[email protected]> wrote:
> I would like to program a (relatively) simple loop to replace the
> values of a variable I created, but I cannot figure it out how to
> write the syntax.
>
> The structure of my data is very simple:
> I have 300 observations and a variable, say x, that in the first cell
> (i.e. for n=1) is equal to 0.1, while it is missing for all other 299
> cells. Data look like:
>
> n x
> 1 0.1
> 2 .
> 3 .
> 4 .
> .
> .
> .
> .
> .
> 299 .
> 300 .
>
> I would like the loop to replace the missing values of my variable by
> going from cell 2 to cell 300, and to have a replace that would be at
> a 0.1 intervals, so as to obtain data that look like:
>
> n x
> 1 0.1
> 2 0.2
> 3 0.3
> 4 0.4
> .
> .
> .
> .
> .
> 299 29.9
> 300 30
>
> I can obviously do it by hand, but a loop would be naturally much more
> efficient!
> Does anyone know how to make it?
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