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Re: st: How to make a code faster - alternatives to egen var = concat(vars) ?,


From   Antoine Terracol <[email protected]>
To   [email protected]
Subject   Re: st: How to make a code faster - alternatives to egen var = concat(vars) ?,
Date   Thu, 17 Jun 2010 23:23:59 +0200

Actually it works if the group variables are all positive integers. otherwise you would have to deal with the "." for decimal values. Doable, but a bit tedious...

Antoine

On 17/06/2010 23:17, Antoine Terracol wrote:
This might not be the most efficient way, but it works:

capture program drop mymean
program define mymean, byable(recall)
syntax varname
marksample touse
local groupname ""
foreach var of local _byvars {
local a =`var'[_byn1()]
if "`a'"=="." {
local a "missing"
}
local groupname "`groupname'`a'"
}
su `varlist' if `touse'
scalar mean`groupname'=r(mean)
end

scalar drop _all
sysuse auto, clear
bysort foreign rep78 : mymean price
scalar dir


Antoine


On 17/06/2010 16:56, Tiago V. Pereira wrote:
Thank you so much again, Antoine!

Yes, this is a very efficient way! However, I could not figure out how I
can save the combination of the categorical variables that a specific
meanX refers to.

For example, the commands

sysuse auto, clear
bysort foreign rep78 : mymean price
scalar dir

show a list of scalars containing the mean of the ith combination, but I
don't know if the mean10 refers to the combination "foreign = Foreign,
rep78 =4" or "foreign = Foreign, rep78 = 5"


[Actually I do in this specific case if I take a look at each value from
the output.]

Nevertheless, assuming a very large number of categorical variables
(n>10), I cannot write a loop and say that mean2451 refers to the
combination x1==0 x2==0 x3==2 x4==0 x5==2 and x6==1. I want to summarize
the mean of this combination in group 1 and generate a separate variable
for group 2.


for example

bysort x1 x2 x3 x4 x5 x6 : mymean score if group==1

*/ yes, -mymean- needs further amendments to have this option

replace score = mean2451 if
group==2&x1==0&x2==0&x3==2&x4==0&x5==2&and&x6==1


So, In this case I know that mean2451 comes from the combination
x1==0&x2==0&x3==2&x4==0&x5==2&and&x6==1 from group 1 and I replace its
value for all subjects from group 2 having an identical combination.


This is getting tough, but you have any additional tips, I will be really
very grateful!

Thanks again.

Tiago





















Tiago,

You would have to define a -byable- -program-, such as:

capture program drop mymean
program define mymean, byable(recall)
syntax varname
marksample touse
su `varlist' if `touse'
local a= _byindex()
scalar mean`a'=r(mean)
end

sysuse auto, clear
bysort foreign rep78 : mymean price
scalar dir

Antoine

On 17/06/2010 15:47, Tiago V. Pereira wrote:
Thanks, Antoine!

But for each combinations, I want to save a local containing the
r(mean).
Is it possible to do that using -bysort-?

Tiago


---------------
Dear statalisters,

I am working on a stata code, and I need some advice.

I have n categorical variables that assumes values equal to 0, 1 or 2.
My
objective is to summarize a continuous variable (say, age) by all
possible
combinations of these categorical variables.


For example, suppose I have 5 categorical variables (x1, x2, x3, x4 and
x5):


sum age if x1==0&x2==0&x3==0&x4==0&x5==0

then

sum age if x1==0&x2==0&x3==0&x4==0&x5==1

then

sum age if x1==0&x2==0&x3==0&x4==0&x5==2

and so forth.


What I am doing is the following: (1) I generate a string of the
categorical variables

egen combination = concat(x1 x2 x3 x4 x5)

(2) convert them to numeric

encode combination, gene (y)

and loop over the values of the new variable y to summarize the
continuous
variable

forvalues i = 1/`some_max_value' {

sum age if y=`i'

}

This naïve solution works very well for small samples (_N<1000) and
small
number of categorical variables (5 to 7). But when I need
investigate in
a
larger sample with a larger number of categorical variables, this code
is
highly inefficient (e.g. slow).

Do you have any suggestions to make this procedure faster in larger
data
sets?

Thanks in advance!

Tiago






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