Hans,
You can do this with the c(current_date) and c(current_time) system
values.
forvalues i = 1/10 {
di `i'
di c(current_date)
di c(current_time)
}
Friedrich Huebler
--- "Hans J. Baumgartner" <[email protected]> wrote:
> I programmed up a routine that takes several days. To gauge how
> long it lasts until finished I would like to display the day
> and hour, when a new loop starts.
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