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RE: st: graphing median values against time


From   Timothy Mak <[email protected]>
To   "[email protected]" <[email protected]>
Subject   RE: st: graphing median values against time
Date   Fri, 28 Mar 2014 15:29:05 +0800

The command -lgraph- that I wrote is for exactly this kind of problem if you don't want to create all the variables before plotting a graph. 
You can see it by typing: 
ssc des lgraph

Tim

-----Original Message-----
From: [email protected] [mailto:[email protected]] On Behalf Of Donald Spady
Sent: 28 March 2014 08:59
To: Statalist Statalist
Subject: Re: st: graphing median values against time

Nick
  It works.  Just as I needed. Many thanks.
John: That suggestion didn't work the way I wanted it to, but thanks for the idea.

Don
On Mar 27, 2014, at 5:48 PM, Nick Cox <[email protected]> wrote:

> Sure. If you use -egen-'s -median()- and -mean()- functions to get the
> variables you want, then it's any graph you want.
> 
> As the median and mean values are repeated, don't plot them repeatedly.
> 
> Here are some dopey examples.
> 
> . webuse grunfeld
> 
> . egen median = median(invest), by(year)
> 
> . egen mean = mean(invest), by(year)
> 
> . egen tag = tag(year)
> 
> . line mean median year if tag
> 
> For finer subdivisions, just use more variables as arguments to -by()-.
> 
> Nick
> [email protected]
> 
> 
> On 27 March 2014 22:34, Donald Spady <[email protected]> wrote:
>> Dear all
>> I want to graph the median and mean values of a series of variables against a time variable (on the X axis) and with the option of stratifying the variables by another one (such as sex or disease state).  I think I can do this by collapsing the data but is it possible to do this while retaining the data set in its 'original' state.  I have searched the archives and the reference manuals but have not come up with anything that seems to be what I want.
>> In many ways what I would like is a box plot with JUST the median (or mean) being plotted: no box, no outliers.  Is that possible.
>> 
>> Thanks
>> Don
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