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Re: st: Use egen command with time series operator
From
Prakash Singh <[email protected]>
To
statalist <[email protected]>
Subject
Re: st: Use egen command with time series operator
Date
Thu, 28 Nov 2013 15:26:52 +0530
Dear Catharina
I just checked with dummy data and realized that you need to generate
the lagged variable first and then the syntex (egen mean_x1 =
mean(l.x1), by(ID YEAR)) will work fine.
Prakash
On Thu, Nov 28, 2013 at 2:38 PM, Klepsch, Catharina <[email protected]> wrote:
> Dear Prakash,
>
> thank's for the advice, but this doesn't work, too.
>
> Any other ideas?
>
> -----Ursprüngliche Nachricht-----
> Von: [email protected] [mailto:[email protected]] Im Auftrag von Prakash Singh
> Gesendet: Donnerstag, 28. November 2013 10:04
> An: statalist
> Betreff: Re: st: Use egen command with time series operator
>
> Dear Catharina
> try this
> egen mean_x1 = mean(l.x1), by(ID YEAR)
>
> Hope it helps you.
>
> Prakash
>
> On Thu, Nov 28, 2013 at 1:33 PM, Klepsch, Catharina <[email protected]> wrote:
>> Dear Stata Users,
>>
>> I was wondering whether it is possible to use the egen command with time series operators.
>> For example, I tried to generate the mean value for a lagged variable and used:
>>
>> sort ID YEAR
>> egen mean_x1 = mean(l.x1)
>>
>> Unfortunately, there occurs an error message which states:
>> not sorted r(5)
>>
>> I'm not quite sure why this happens, because I sorted the data before. Even if I type:
>> bys ID YEAR: egen mean_x1 = mean(l.x1)
>>
>> the same error message occurs.
>>
>> Any ideas how I can fix that? Please consider that it is not reasonable for my programming to first generate the lag/lead and then generate the mean.
>>
>> Thank's for any help.
>> Catharina
>>
>>
>>
>>
>>
>> *
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>
> *
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*
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