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Re: st: Creating a dummy variable under certain conditions


From   Nick Cox <[email protected]>
To   [email protected]
Subject   Re: st: Creating a dummy variable under certain conditions
Date   Sat, 2 Jun 2012 13:56:02 +0100

This looks OK as long as you substitute -viol- for -gvkey-. The
previous values  concerned are for -viol-, not -gvkey-.

Nick

On Sat, Jun 2, 2012 at 1:51 PM, Abhimanyu Arora
<[email protected]> wrote:

> Try this if your data is -xtset-ted
> gen new_viol_dummy=L.gvkey+L2.gvkey+L3.gvkey+L4.gvkey==0

> On Sat, Jun 2, 2012 at 2:06 PM, sebas nicaise <[email protected]>
>
>> I am struggeling with creating a new dummy variable. I have a very large
>> (unbalanced) panel dataset that looks like this:
>>
>>
>>
>> date gvkey viol
>> 1997q1 1021 0
>> 1997q2 1021 0
>> 1997q3 1021 0
>> 1997q4 1021 0
>> 1998q1 1021 1
>> 1998q2 1021 0
>> 1998q3 1021 0
>> 1998q4 1021 1
>> 1999q1 1021 0
>>
>> 1999q2 1021 0
>>
>> 1999q3 1021 0
>> 1999q2 1023 0
>> 1999q3 1023 1
>> 1999q4 1023 0
>> 2000q1 1023 0
>> 2000q2 1023 1
>>
>>
>> Where date is calender quarter, gvkey is the company identifier and viol a
>> dummy which equals 1 if the firm is in violation of a covenant in a private
>> debt contract.
>>
>>
>>
>> The problem is that I have to create a new dummy variable ( new violation)
>> which meets certain conditions.
>>
>> The new violation dummy is only allowed to be 1 if in the previous 4
>> quarters of a certain company (gvkey) is 0.
>>
>>
>>
>> This means for example that:
>>
>>
>>
>> date gvkey viol Newviolation
>> 1997q1 1021 0       0
>> 1997q2 1021 0       0
>> 1997q3 1021 0       0
>> 1997q4 1021 0       0
>> 1998q1 1021 1       1
>> 1998q2 1021 0       0
>> 1998q3 1021 0       0
>> 1998q4 1021 1       0
>> 1999q1 1021 0       0
>>
>> 1999q2 1021 0       0
>>
>> 1999q3 1021 0       0
>> 1999q2 1023 0       0
>> 1999q3 1023 1       0
>> 1999q4 1023 0       0
>> 2000q1 1023 0       0
>> 2000q2 1023 1       0
>>
>>
>>
>> I do not know how to tell Stata to create this variable, Hope someone is
>> so kind to help me.

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