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RE: st: Creating choice indicator!
From
Nick Cox <[email protected]>
To
"'[email protected]'" <[email protected]>
Subject
RE: st: Creating choice indicator!
Date
Tue, 20 Mar 2012 18:24:08 +0000
Alternatively, look upwards!
ceil(5 * runiform())
Nick
[email protected]
Scott Merryman
For a random integer between 1 and 5 the code should be :
1 + floor(5*runiform())
On Tue, Mar 20, 2012 at 12:32 PM, Peter Grand <[email protected]> wrote:
> @ Scott: Exactly, thank you very much!
>
> @ Joerg: Sorry, if I have not been able to correctly specify my request.
>
> Again, thank you for your efforts!
>
Scott Merryman [[email protected]]
> Something like this?
>
>
> clear
> set obs 5
> gen id = _n
> expand 5
> sort id
>
> bys id: gen order = _n
> gen chosen = 0
> levelsof id, local(levels)
> foreach l of local levels {
> if runiform() < .5 { //probability that id is chosen
> local a = round(1 +4*runiform(),1)
> qui replace chosen= 1 if order == `a' & id == `l' //1 of 5
> alternatives is chosen
>
> }
> }
> drop order
> l
On Tue, Mar 20, 2012 at 11:51 AM, Peter Grand <[email protected]> wrote:
>> How can I create a random binary variable which indicates either only one chosen alternative or none of them within an id variable, e.g. 5 choices for each individual id :
>>
>>
>> id chosen
>> 1 0
>> 1 0
>> 1 1
>> 1 0
>> 1 0
>> 2 0
>> 2 0
>> 2 0
>> 2 0
>> 2 0
>> 3 0
>> 3 1
>> 3 0
>> 3 0
>> 3 0
>>
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