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# Re: st: output survival analysis

 From Nick Cox To statalist@hsphsun2.harvard.edu Subject Re: st: output survival analysis Date Fri, 29 Jul 2011 10:19:20 +0100

\ln_the means ln(theta) as you can verify for yourself.

. di ln(7.76747)
2.0499445

No doubt you can fudge an R^2 for yourself, but that is foisting
least-squares ideas where they are not central to the analysis:

FAQ     . . . . . . . . . . . . . . . . . . . . . . . Do-it-yourself R-squared
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . .  N. J. Cox
9/03    How can I get an R-squared value when a Stata command
does not supply one?
http://www.stata.com/support/faqs/stat/rsquared.html

Nick

On Fri, Jul 29, 2011 at 9:28 AM, Yusvita Triwiadhian S.
<07.5544@stis.ac.id> wrote:

> i'm running gompertz gamma frailty for survival analysis and get
> output like this :
>
> t              haz.ratio      std.error   z        P>|z|            95% CI
>
> /ln_the      2.04994     0.55177   3.72      0,000         0.96850 ; 3.13139
> theta         7.76747     4.28582                               2.6340
>  ;  22.90569
>
> i want to ask about function of /ln_the ?? what is it means?
>
> then, if i want to know how many percent predictor variable can
> explain variation data of respon variable, (like square R if in linear
> regression), what must i do??

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