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From | Nick Cox <njcoxstata@gmail.com> |
To | statalist@hsphsun2.harvard.edu |
Subject | Re: st: output survival analysis |
Date | Fri, 29 Jul 2011 10:19:20 +0100 |
\ln_the means ln(theta) as you can verify for yourself. . di ln(7.76747) 2.0499445 For "gompertz" read "Gompertz". No doubt you can fudge an R^2 for yourself, but that is foisting least-squares ideas where they are not central to the analysis: FAQ . . . . . . . . . . . . . . . . . . . . . . . Do-it-yourself R-squared . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . N. J. Cox 9/03 How can I get an R-squared value when a Stata command does not supply one? http://www.stata.com/support/faqs/stat/rsquared.html Nick On Fri, Jul 29, 2011 at 9:28 AM, Yusvita Triwiadhian S. <07.5544@stis.ac.id> wrote: > i'm running gompertz gamma frailty for survival analysis and get > output like this : > > t haz.ratio std.error z P>|z| 95% CI > > /ln_the 2.04994 0.55177 3.72 0,000 0.96850 ; 3.13139 > theta 7.76747 4.28582 2.6340 > ; 22.90569 > > i want to ask about function of /ln_the ?? what is it means? > > then, if i want to know how many percent predictor variable can > explain variation data of respon variable, (like square R if in linear > regression), what must i do?? * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/