Re: st: if expression involving a variable in a while loop

[Daifeng He <dhe.statlist@gmail.com>]

Thanks, Oliver.  The codes work now.  Appreciate the help!

Best,
Daifeng

On Wed, Jul 13, 2011 at 3:25 PM, Oliver Jones
<ojones@wiwi.uni-bielefeld.de> wrote:
> Sorry my fault.
> Of course one has to reset the local sum back to 0 once it has reached the
> 0.95 for
> the specific row we are looking at currently.
>
>
> Am 13.07.2011 21:22, schrieb Daifeng He:
>>
>> Thanks, Scott.  The code works and it's exactly what I had wanted.
>>
>> Oliver, your codes look reasonable to me too but when I run them, only
>> the first obs is filled in with values for the two newly-generated
>> variables.  I will try to figure it out.
>>
>> Joerg, yes, my weight variables are sorted for each obs, but your
>> codes are illuminating and I learned from them too.
>>
>> Guys, thanks for all your help!
>>
>> Kind regards,
>> Daifeng
>>
>>
>>
>> On Wed, Jul 13, 2011 at 2:56 PM, Scott Merryman
>> <scott.merryman@gmail.com>  wrote:
>>>
>>> Like this?
>>>
>>> clear
>>> input  v1  v2   v3   v4   v5   v6   v7
>>> .96 .04 .0 0 0 0 0
>>> .5 .3 .1 .03 .03 .03 0.01
>>> .4 .2 .2  .15 .03 0.015 .002
>>> .3 .3 .37 .03 0 0 0
>>> .9 .08 .02 0 0 0 0
>>> end
>>>
>>> gen sum = 0
>>> gen var_count = 1
>>> qui {
>>> forv i = 1/7 {
>>>        replace sum = sum + v`i' if sum<.95
>>>        replace var_count = var_count + 1 if sum<.95
>>> }
>>> }
>>>
>>> l
>>>
>>> Scott
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