Re: st: if expression involving a variable in a while loop

[Oliver Jones <ojones@wiwi.uni-bielefeld.de>]

Sorry my fault.
Of course one has to reset the local sum back to 0 once it has reached the 0.95 for
the specific row we are looking at currently.


Am 13.07.2011 21:22, schrieb Daifeng He:
> Thanks, Scott.  The code works and it's exactly what I had wanted.
>
> Oliver, your codes look reasonable to me too but when I run them, only
> the first obs is filled in with values for the two newly-generated
> variables.  I will try to figure it out.
>
> Joerg, yes, my weight variables are sorted for each obs, but your
> codes are illuminating and I learned from them too.
>
> Guys, thanks for all your help!
>
> Kind regards,
> Daifeng
>
>
>
> On Wed, Jul 13, 2011 at 2:56 PM, Scott Merryman
> <scott.merryman@gmail.com>  wrote:
> > Like this?
> >
> > clear
> > input  v1  v2   v3   v4   v5   v6   v7
> > .96 .04 .0 0 0 0 0
> > .5 .3 .1 .03 .03 .03 0.01
> > .4 .2 .2  .15 .03 0.015 .002
> > .3 .3 .37 .03 0 0 0
> > .9 .08 .02 0 0 0 0
> > end
> >
> > gen sum = 0
> > gen var_count = 1
> > qui {
> > forv i = 1/7 {
> >         replace sum = sum + v`i' if sum<.95
> >         replace var_count = var_count + 1 if sum<.95
> > }
> > }
> >
> > l
> >
> > Scott
> > *
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