Bookmark and Share

Notice: On April 23, 2014, Statalist moved from an email list to a forum, based at

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

Re: st: xtmixed with nonrtolerance. What happens?

From   Anders Alexandersson <>
Subject   Re: st: xtmixed with nonrtolerance. What happens?
Date   Fri, 24 Jun 2011 08:54:45 -0400

I too would like to see the frequency distribution of your original
dependent variable (i.e., before standardization).
and, like Maarten, I would use xtmepoisson instead of xtmixed if the
outcome variable is a count.

Lukas, what is your sample population, e.g, the 40 or the 130 countries?
Why do you need completely balanced data (no missing values)?

Anders Alexandersson

Lukas wrote:
> 1) Concerning the missings, i took care to delete all data i don't have the complete time series for.
> This means that i had to drop from 130 countries over a 20 years period to 40 countries over a 15 years
> period. On the other hand, there are deffinitely no missing values.

On Fri, Jun 24, 2011 at 6:30 AM, Maarten Buis <> wrote:
> --- On Fri, Jun 24, 2011 at 12:11 PM, "Lukas Bösch" wrote:
>> One more information:
>> When i run the modell only with the complete export time series. Without any zeroes in the dependent data, the output looks like this:
> <snip>
>>                 sd(R.genus) |   2.93e-06   .0221629             0
> I would not trust that result. First, leaving out 0s means you select
> on your dependent variable, which is a very bad idea. Second, your
> results indicate that the genus variation is de facto 0 (2.93e-6 =
> 0.000000293), which given your context is very unlikely.

*   For searches and help try:

© Copyright 1996–2018 StataCorp LLC   |   Terms of use   |   Privacy   |   Contact us   |   Site index