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# Re: st: Box-Tidwell Test

 From Nick cox To "statalist@hsphsun2.harvard.edu" Subject Re: st: Box-Tidwell Test Date Tue, 26 Apr 2011 11:49:55 +0100

Here is another take. Consider adding the square of a 0-1 variable as an extra predictor to check linearity. But it's the same! Thus there is no progress this way.
```
Nick

On 26 Apr 2011, at 09:40, lisenger@students.mail.uni-mannheim.de wrote:

```
```Hi

Sorry for the vague explanations.

```
I want to check in how far being interested in a political scnadal and evaluating the scandal as an important problem, impacts the vote intentions of the people. My exampekl is the CDU- party finance scandal in Germany in 1999/2000.
```
My dependent variable is vote intention

1 = vote intention for CDU/CSU 0 = vote intention for other parties

Independent Variables:

subject orientation: 1 = interested in scandal 0 = not interested
```
problem orientation: 1 = scandal importatnt problem 0 = scandal not important
```

My logistic regression: logit voteUnion subject problem

```
My "not working" I mean that the Box-Tidwell test does not give any results. Normally below the regression, there would be columns with the results, yet in my case nothing
```

Iteration 0:  Deviance =  46385.51
Iteration 1:  Deviance =  46385.51 (change =         0)

[Total iterations: 0]

Box-Tidwell regression model

```
Logistic regression Number of obs = 36278 LR chi2(2) = 228.82 Prob > chi2 = 0.0000 Log likelihood = -23192.755 Pseudo R2 = 0.0049
```
```
--- --- --- --------------------------------------------------------------------- wabsunion | Coef. Std. Err. z P>|z| [95% Conf. Interval] ------------- +---------------------------------------------------------------- themen | -.3546749 .0278373 -12.74 0.000 -.409235 -.3001148 problem | -.3162207 .0492572 -6.42 0.000 -.4127631 -.2196784 _cons | -.5600199 .0126023 -44.44 0.000 -.5847199 -.5353199 --- --- --- ---------------------------------------------------------------------
```Deviance:46385.509.

.
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