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st: R: % of people lying under a certain percentage of median income - (flag: Stata 9/2 SE)
From
"Carlo Lazzaro" <[email protected]>
To
<[email protected]>
Subject
st: R: % of people lying under a certain percentage of median income - (flag: Stata 9/2 SE)
Date
Sun, 3 Oct 2010 13:37:31 +0200
Dear Caterina, what follows can do the trick:
--------- code begins---------------
set obs 100
g income=100000*uniform()
qui sum income,d
scalar A= r(N)
count if income < .2*r(p50)
di r(N)/A
--------- code ends---------------
Kind Regards and Have a Nice Sunday,
Carlo
-----Messaggio originale-----
Da: [email protected]
[mailto:[email protected]] Per conto di Caterina Astarita
Inviato: domenica 3 ottobre 2010 11.32
A: [email protected]
Oggetto: st: % of people lying under a certain percentage of median income
Dear statalister,
I would like to calculate the percentage of families having an
income that lies below a certain percentage below the median
income, let's say the 20% of the median income. Is there any
command in Stata that performs this kind of calculus?
Thank you
Caterina
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