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Re: st: re: one-sided p-value using test x1=x2

From   [email protected]
To   [email protected]
Subject   Re: st: re: one-sided p-value using test x1=x2
Date   Wed, 30 Sep 2009 22:28:22 +0200

Hello Kit,

thank you very much for the explanation!
Does it mean, that if I have two negative coefficients and want to test whether the one (which has the more negative point estimate) is significantly more negative then the other, I can divide the p-value by two and reject (or resepctively not reject) the null-hypothesis?


Zitat von Kit Baum <[email protected]>:

Recognize that any F statistic with one numerator d.f. and K
denominator d.f.s is the square of a t-statistic with K d.f., and has
exactly the same p-values. So you can always turn an F test that
involves one numerator d.f. (which may involve more than two
coefficients, by the way) into a t-test.

When doing one-sided tests, the important thing is to recognize that if
the point estimate is on the 'wrong' side, you can never reject. So if
Ho: \beta_1 >= \beta_2 vs Ha: \beta_1 < \beta2,  and your point
estimate for \beta_1 is greater than your estimate for \beta_2, you can
never reject the null. You need a \beta_1 that is sufficiently less
than \beta_2 to do so. That said, if you're on the 'right' side, you
can halve the reported p-value, as it is calculated for a two-tailed

sysuse auto,clear
reg price i.foreign#c.mpg
test 0b.foreign#c.mpg = 1.foreign#c.mpg

In this example the domestic coefficient (\beta_1) is less than the
foreign coefficient (\beta_2), and on a one-tailed test we can reject
at better than 99%.

Kit Baum   |   Boston College Economics & DIW Berlin   |
                              An Introduction to Stata Programming  |
   An Introduction to Modern Econometrics Using Stata  |

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