<>
Ariel wants to take note that the underlying value of the "month" variable
is "570" - the # of months that have passed since January of 1960. The rest
is taken care of via -format-. So the -string- that he suspects to be the
solution does not play a role here. Indeed, -string-s are useful to -input-
dates, but immediately upon completion of the -input-, they ususally get
converted to a "%td" value...
******
clear*
input date
17374
end
format date %tdNN/DD/CCYY
gen month=mofd(date)
format month %tmMonth_CCYY
l, noo
******
HTH
Martin
-----Ursprüngliche Nachricht-----
Von: [email protected]
[mailto:[email protected]] Im Auftrag von Ariel Linden,
DrPH
Gesendet: Donnerstag, 27. August 2009 05:37
An: [email protected]
Betreff: st: extracting month and year from a date variable
Hi Fellow Stata Listservers,
I am trying to generate a variable that contains only the month and year,
extracted from another complete date variable. The ultimate intent is to
aggregate a given outcome by the month/year.
So for example, the original date value is 17374, which is displayed as
07/27/2007. I would like to generate a variable that is "Jul 2007" or
"07_2007" (I am not picky on the style, this is just to allow me to
aggregrate by this variable).
I get the feeling that I will have to convert this to a string and then
generate the variable with a substr statement, but I hope there is an easier
way.
Thanks in advance
Ariel
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