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From |
"Bastian Steingros" <[email protected]> |

To |
[email protected] |

Subject |
st: benchmarking + determine the peers |

Date |
Tue, 30 Sep 2008 16:32:36 +0200 |

Dear Stata users, I am searching a function in stata to program peer groups. In my benchmarking study about American industries I want to compare companies by its sales, earnings etc. I use the three digit industry code to classify the industries (sic-codes). The peer group must be within the same industry. Here, the purpose is to compute the mean or median of the sales and to see if the respective firm's performance is below or above the mean or the median. But, the peer group of firm X contains all the companies with the same digit code but *not* firm X (otherwise I would compare X with itself) To conclude: year sic-code firm sales mean median 1990 333 X 10 ? ? 1990 333 Y 20 ? ? 1990 333 Z 30 ? ? --------------------------------------------- 1990 334 A 21 ? ? 1990 334 B 5 ? ? --------------------------------------------- 1991 etc. ... so, in 1990 the peer group mean/median for X must contain (20+30) but not 10 the peer group mean/median for Y must contain (10+30) but not 20 the peer group mean/median for Z must contain (10+20) but not 30 and so on... is there a way to program is stata something like: by year sic-code, sort: egen median/mean *without the sales of the firm X / firm Y etc.* (Please note, it is basically more important for me to obtain the *median* than the mean peer group due to the outlier problem of the mean function.) So, please help me find a solution to the median peer group first. Many thanks in advance! Bastian -- Psssst! Schon vom neuen GMX MultiMessenger geh�rt? Der kann`s mit allen: http://www.gmx.net/de/go/multimessenger * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

**Follow-Ups**:**Re: st: benchmarking + determine the peers***From:*"Eva Poen" <[email protected]>

**st: RE: benchmarking + determine the peers***From:*"Martin Weiss" <[email protected]>

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