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st: Re: st: Re: st: Σχετ: st: diving values of a column with other values of the same column
From
Nick Cox <[email protected]>
To
[email protected]
Subject
st: Re: st: Re: st: Σχετ: st: diving values of a column with other values of the same column
Date
Wed, 6 Feb 2013 00:28:00 +0000
This might help. I can't say whether it fits data you don't show us.
Also, a variable that is zz in some cases and 0 in other might be
numeric and might be string, depending on what "zz" means, so its sort
order is unpredictable.
bysort country date (specific) : gen values2 = values[1]/values[2]
Nick
On Wed, Feb 6, 2013 at 12:17 AM, Nick Cox <[email protected]> wrote:
> I think you have to tell us the rule your data follow. Otherwise the
> reply to "my data are more complicated than that" is just "so your
> code needs to be more complicated than that".
>
> For a general discussion, see the Speaking Stata column in Stata
> Journal 11(2) from 2011:
>
> http://www.stata-journal.com/article.html?article=dm0055
>
> Nick
>
> On Wed, Feb 6, 2013 at 12:07 AM, Tzaloupas Dimitrov
> <[email protected]> wrote:
>
>> thank you very much scott. The only problem is that my real panel is unbalanced. So it is not always 3 obs/ 3 obs
>>
>> Is there a way to modify your code so as to take into account this unbalanced panel data set?
>
> Scott Merryman <[email protected]>
>
> On Tue, Feb 5, 2013 at 3:34 PM, Tzaloupas Dimitrov
>
>>> I have the following excel file which I import into Stata
>>> Country overall specific dates values
>>> DD gg 0 01/11/2001 5
>>> DD gg 0 01/12/2001 2
>>> DD gg 0 01/01/2001 3
>>> DD gg zz 01/11/2001 15
>>> DD gg zz 01/12/2001 12
>>> DD gg zz 01/01/2001 13
>>> EE gg 0 01/11/2001 0.5
>>> EE gg 0 01/12/2001 0.2
>>> EE gg 0 01/01/2001 0.3
>>> EE gg zz 01/11/2001 25
>>> EE gg zz 01/12/2001 122
>>> EE gg zz 01/01/2001 2 3
>>>
>>> For each country separately(DD and EE) I would like to divide the values that correspond to specific==zz by the values that correspond to speciffic==0
>>>
>>> For example, for DD I want to divide the vector of values (15 12 13) that corresponds to specific==zz by the vector (5 2 3) that corresponds to specific==0; so as to construct a new vector of values=(15/5 12/2 13/3)
>>
>>
>> bys country (spec dates) : gen values2 = values/values[_n-3]
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