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From |
Steve Samuels <[email protected]> |

To |
[email protected] |

Subject |
Re: st: RE: Predicting survival at a specific time following generalized gamma regression |

Date |
Wed, 11 Jul 2012 10:57:25 -0400 |

```
Al's advice to transform S(t) is excellent. My previous example
produced confidence limits outside of [0,1] Here's a rewrite e with
the complementary log-log transformation. c(t) = log(-log(S(t)).
Steve
[email protected]
*****************************************
webuse drugtr, clear
streg drug age, dist(gamma) time coeflegend
gen old_t = _t
replace _t = 20
predict t_surv, surv
local myt = 20
#delim ;
predictnl c_`myt' =
cloglog(gammap( _b[kappa:_cons]^(-2),
(_b[kappa:_cons]^(-2))*exp(_b[kappa:_cons]*
(log(`myt')-xb())/exp(_b[ln_sig:_cons])))),
se(se_`myt') ci(lowc_`myt' uppc_`myt');
#delim cr
gen surv_`myt' = 1- invcloglog(c_`myt')
gen s_low_`myt' =1- invcloglog(uppc_`myt')
gen s_upp_`myt' =1 -invcloglog(lowc_`myt')
sum t_surv surv_* s_low* s_upp*
list t_surv surv_* s_low* s_upp* in 1/2
*************************************
On Jul 11, 2012, at 9:32 AM, Feiveson, Alan H. (JSC-SK311) wrote:
Thomas - If you look up the expression for the survival function S(t) for the generalized gamma (in the manual under -streg-) you can see that S(t) is a complicated function of "Xb" - the (linear predictor) for a particular value of time, the covariates, and the ancillary parameters kappa and sigma. You can use -nlcom- or -nlpredict- to get confidence limits for this function. Better, because S(t) is bounded between 0 and 1, you can get confidence limits for logit(S(t)) or probit(S(t)), which covers all values, then transform back to guarantee that your limits will lie between 0 and 1.
I know this is messy. Perhaps there are more direct ways of doing this. We need something like -margins- to work for predicting survival after running -streg-.
Al Feiveson
-----Original Message-----
From: [email protected] [mailto:[email protected]] On Behalf Of Thomas Inns
Sent: Wednesday, July 11, 2012 6:25 AM
To: [email protected]
Subject: st: Predicting survival at a specific time following generalized gamma regression
Hello,
If someone could kindly take the time to help me I'd be very appreciative. I'm try to predict the probability of survival at one year following infection.
I'm using a parametric survival model with a generalized gamma distribution and an accelerated failure-time metric (streg, distribution(gamma) time).
I have used the streg postestimation command "predict, surv", but I can't work out how to put a confidence interval around my predicted survival probability at one year following infection. Is this possible? And if so, do you know how I might do this?
Below is my code, inspired by Bobby Gutierrez's post at http://www.stata.com/statalist/archive/2010-12/msg00647.html.
Thanks,
Thomas Inns
*************CODE BEGINS*************
streg i.ribolog i.gender i.agetri i.year i.ftbin##i.trustapp, d(gamma) time
****predict conditional survivor function (probability of survival past time t)
****(time t = 1 year)
*prediction at t = 365.25
gen tt = 365.25
*keep old _t
gen t_old = _t
*put in _t you want to use for prediction
replace _t = tt
*predict surival past time _t (one year)
predict t_surv, surv
label var t_surv "gamma prediction"
*summarise these predictions
summ t_surv, detail
**************CODE ENDS**************
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```

**References**:**st: Predicting survival at a specific time following generalized gamma regression***From:*Thomas Inns <[email protected]>

**st: RE: Predicting survival at a specific time following generalized gamma regression***From:*"Feiveson, Alan H. (JSC-SK311)" <[email protected]>

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