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Re: st: question about local and var[n]
From
Matthew White <[email protected]>
To
[email protected]
Subject
Re: st: question about local and var[n]
Date
Tue, 25 Oct 2011 02:25:25 -0400
You probably want:
local city = ID[1]
not:
local city ID[1]
The latter just assigns the string "ID[1]" to `city'. -display
"`city'"- will display "ID[1]" not "ny". The former, on the other
hand, first evaluates the expression ID[1], THEN assigns the result to
`city'. ID[1] will evaluate to "ny", which is then assigned to `city'.
-display "`city'"- will display "ny".
Hope that helps!
Best,
Matt
On Tue, Oct 25, 2011 at 1:47 AM, G. Dai <[email protected]> wrote:
> Dear all,
> I have one question about the use of local macros.
> For example, assume the date
>
> ID ny_price
> ny 5
> wa 4
>
> set obs 2
> gen str ID=""
> replace ID="ny" in 1
> replace ID="wa" in 2
> gen ny_price=4
> replace ny_price=5 in 1
>
>
> Then My question comes from the following differences:
>
>
> . local city ny
>
> .
> . replace `city'_price=100 in 1
> (1 real change made)
>
>
> However,
>
> . local city ID[1]
> . di `city'
> ny
> . replace `city'_price=100 in 1
> weights not allowed
> r(101);
>
> Why?
> thanks!
> *
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>
--
Matthew White
Data Coordinator
Innovations for Poverty Action
101 Whitney Avenue, New Haven, CT 06510 USA
+1 434-305-9861
www.poverty-action.org
*
* For searches and help try:
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* http://www.stata.com/support/statalist/faq
* http://www.ats.ucla.edu/stat/stata/