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From | Stas Kolenikov <skolenik@gmail.com> |
To | statalist@hsphsun2.harvard.edu |
Subject | Re: st: e(wexp) versus e(wexp): different routines return different things |
Date | Sat, 27 Aug 2011 16:51:41 -0500 |
Nick, the original poster had an issue of some commands returning -e(wexp)- with an equal sign, and others, without it. So the equal sign had to be parsed out. On Sat, Aug 27, 2011 at 2:44 PM, Nick Cox <njcoxstata@gmail.com> wrote: > Too complicated :) > > tempvar wvar > if "`e(wexp)'" == "" generate byte `wvar' = 1 > else generate double `wvar' `e(wexp)' > > On Sat, Aug 27, 2011 at 8:28 PM, Stas Kolenikov <skolenik@gmail.com> wrote: >> Oh those overqualified programmers working in Stata :). Regular >> expressions are an overkill for situation like this. You can achieve >> what you need with the string functions. >> >> tempvar wvar >> if "`e(wexp)'" == "" generate byte `wvar' = 1 >> else { >> local mywexp = subsinstr("`e(wexp)'","=","",1) >> generate double `wvar' = `mywexp' >> } >> >> and then you can pass `wvar'. >> >> On Fri, Aug 26, 2011 at 8:49 PM, Rodini, Mark >> <mrodini@compasslexecon.com> wrote: >>> Greetings, >>> >>> I have a program which executes after I run an estimation procedure, and it does a collapse where weighting is an option. >>> Within the program is the following line: >>> >>> >>> if "`e(wexp)'" != "" { >>> collapse (mean) `y_sample' `xb_sample' [fw `e(wexp)'] >>> } >>> >>> I'm running an estimation using "reg" and one using "newey2". Suppose the name of the weighting variable, should I opt to use it, is "mycount" so for example, I run: >>> >>> reg y high low cows [aw=mycount] >>> >>> and then execute the program. >>> >>> >>> Both estimation routines create as output an estimation "variable" called e(wexp). Note that this is what is passed to the program as indicated above. >>> >>> Here is the kicker: reg returns e(wexp) as "= mycount", but newey2 returns e(wexp) as "mycount" (without the equals sign!) >>> >>> The reg version properly executes the program above, but newey2 gives an error about an inability to weight, since the syntax requires an equals sign. >>> >>> I have tried within the program to create a tempname or tempvar, assign e(wexp) to it and then tried running >>> >>> scalar `wts'=regexr(`e(wexp)',"=","") >>> >>> I then replace the `e(wexp)' in the program with `wts' and add an equals sign explicitly in the program. The idea I was hoping for is that it would replace the "=" with nothing in the macro variable, if one were there. >>> >>> No matter how I try it, it fails, usually with a type mismatch error. I tried adding double quotes, etc. I am assuming that because I'm trying to pass it as a scalar, that is what bombs it. Any thoughts? I'm guessing it's something pretty basic --I'm kind of new to writing complicated programs which pass lots of stuff. >> >> >> >> -- >> Stas Kolenikov, also found at http://stas.kolenikov.name >> Small print: I use this email account for mailing lists only. >> >> * >> * For searches and help try: >> * http://www.stata.com/help.cgi?search >> * http://www.stata.com/support/statalist/faq >> * http://www.ats.ucla.edu/stat/stata/ >> > > * > * For searches and help try: > * http://www.stata.com/help.cgi?search > * http://www.stata.com/support/statalist/faq > * http://www.ats.ucla.edu/stat/stata/ > -- Stas Kolenikov, also found at http://stas.kolenikov.name Small print: I use this email account for mailing lists only. * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/