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RE: st: RE: how can I create deciles by group?

From   Nick Cox <>
To   "''" <>
Subject   RE: st: RE: how can I create deciles by group?
Date   Thu, 7 Jul 2011 11:48:50 +0100

As I understand it, you don't need to create deciles at all for your problem. Why you asked the question in the first place is now something of a mystery! 

As the issue now seems to be how to draw a particular graph, I note that what are called "decile plots" in the paper referred to are just standard scatter plots with a line of equality through the origin. That is achieved by e.g. -twoway scatter ... || function equality = x, ... but naturally you have to calculate what is being plotted first. 

It's impossible for any individual to know about usages of graph terminology across all disciplines, but to me the term "decile plots" conveys only that deciles are being plotted, or that results are being plotted by decile. I wouldn't be surprised by either usage. 


Argyn Kuketayev

in original paper they'd have stub3 variable continuous, which they
would slice into deciles, then compute the actual failure rates within
these deciles and show on Y-axis. that's why they call it decile plot.

in my case, stub3 is discrete, so i don't really need deciles, but
simply groups by stub3. hence, you're right there's no deciles in my
problem, but it's very similar, and i thought the solution would be
the same. i thought there would eb a standard plot called "decile
plot", which i'd plug my data into and get a nice graph

On Wed, Jul 6, 2011 at 7:33 PM, Nick Cox <> wrote:
> Sorry, Argyn, but this makes no sense to me. Where are the deciles?
> Nick
> On Wed, Jul 6, 2011 at 11:02 PM, Argyn Kuketayev
> <> wrote:
>> Nick
>> i'm still having trouble to make it work.
>> i have the variable "stub3", which shows the probability of failure.
>> then i have a variable called "dq", which indicates failures with
>> value 1, and 0 if no failure.
>> so i want to build a decile plot, where on X-axis - stub3, and in
>> Y-axis - the "actual" failure rate in this group.
>> cheers
>> On Wed, Jul 6, 2011 at 4:22 PM, Nick Cox <> wrote:
>>> I drew attention to an -egen- function written by Uli Kohler in that thread.
>>> Nick
>>> On Wed, Jul 6, 2011 at 8:56 PM, Argyn Kuketayev
>>> <> wrote:
>>>> Nick
>>>> I didn't like the solution with a loop. I'm going to try -egen- solution.
>>>> I'm trying to reproduce the Figure 4 in this paper
>>>> cheers
>>>> On Wed, Jul 6, 2011 at 3:46 PM, Nick Cox <> wrote:
>>>>> What's wrong with those answers?
>>>>> Nick
>>>>> On Wed, Jul 6, 2011 at 7:09 PM, Argyn Kuketayev
>>>>> <> wrote:
>>>>>> is there a better way than describes in this thread?

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