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RE: st: variable format


From   "Andreas Drichoutis" <[email protected]>
To   <[email protected]>
Subject   RE: st: variable format
Date   Thu, 10 Mar 2011 21:44:18 +0200

Well it didn't. I tried gen varnew=round(var,.01) and all it did is to
create a copy of the original variable. Values are displayed with 2 decimals
but the actual value is 7 decimals long.

Andreas

-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Sarah Edgington
Sent: Thursday, March 10, 2011 9:28 PM
To: [email protected]
Subject: RE: st: variable format

.
What do you mean when you say the round function doesn't work?  It really
seems like that should be your best bet.
-Sarah 

-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Andreas
Drichoutis
Sent: Thursday, March 10, 2011 11:25 AM
To: [email protected]
Subject: RE: st: variable format

My concern is the actual value and neither the round function works nor
changing the format to  %3.2f  . 

Any other ideas?

Andreas


-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Joerg Luedicke
Sent: Thursday, March 10, 2011 9:20 PM
To: [email protected]
Subject: Re: st: variable format

On Thu, Mar 10, 2011 at 1:53 PM, Joerg Luedicke <[email protected]>
wrote:
> On Thu, Mar 10, 2011 at 1:27 PM, Andreas Drichoutis 
> <[email protected]>
wrote:
>> Dear all,
>>
>> Some variables in my dataset are stored as float %8.0g . I need to 
>> have exactly 2 decimals for these variables, however Stata formats 
>> these with more decimals e.g., it stores the value of 8.77 as 8.7700005.
>>
>> How do I convert variables to 2 decimals only.
>
> http://lmgtfy.com/?q=stata+variable+format
>
> in your case it could be something like
>
> format  %3.2f  yourvariable
>
> if you numbers have no more than 3 digits
>
> J.
>

...might need to add that if your concern is not the format but the actual
value, you can round them using the round function together with generate or
replace (-help round-). So if you wanted to replace your data you could do
(if x is your variable):

replace x =round(x, .01)


J.

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