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Re: st: Question regarding metaregression
From
Austin Nichols <[email protected]>
To
[email protected]
Subject
Re: st: Question regarding metaregression
Date
Thu, 10 Feb 2011 11:39:52 -0500
Chan Yoon <[email protected]>:
I assume you are referring to a relative risk (ratio) point estimate y
and a confidence interval with lower bound x and upper bound z which
are not equidistant from y, i.e. they were computed as the antilog of
the endpoints of a confidence interval around ln(y).
The log of the relative risk ln(y) has a sampling distribution that is
approximately normal, and the resulting confidence interval (lnx,lnz)
is symmetric around ln(y), i.e.,
ln(x) = ln(y) - SE*1.96
ln(z) = ln(y) + SE*1.96
approximately, where 1.96 should be replaced with the appropriate
critical value. So your SE is
SE = [ln(y)-ln(x)]/1.96 = [ln(z)-ln(y)]/1.96
and if you have x, y, and z measured with finite precision, maybe you want
SE = [ [ln(y)-ln(x)]/1.96 + [ln(z)-ln(y)]/1.96 ]/2
On Thu, Feb 10, 2011 at 5:06 AM, Chan Yoon <[email protected]> wrote:
> I have a problem using metareg commend.
> To use commend. wsse (selogrr) I have to have selogrr value.
> But I only have rr with 95% confidence interval( 95% ci)
> Is there a way I can use metareg with rr and upper limit and lower limit of 95% ci? Or is there a way to obtain selogrr from rr and ci?
> I would very much appreciate your help. Thank you.
> Chan.
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