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| From | Nick Cox <n.j.cox@durham.ac.uk> |
| To | "'statalist@hsphsun2.harvard.edu'" <statalist@hsphsun2.harvard.edu> |
| Subject | st: RE: RE: comparing different means using ttest |
| Date | Thu, 16 Dec 2010 18:16:48 +0000 |
A senior Stata user, who might not want to be named, pointed out the counter-example of a Poisson variable. Clearly correct: if you know that your variable is Poisson, then the mean is also the variance. Nick n.j.cox@durham.ac.uk Nick Cox [...] any more than the mean of anything tells you about its variability. [...] * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/