<>
My -irecode- approach creates a variable with values that range from 1 to 5.
If ever you wanted irregularly spaced values (your x1 to x5), you could
enter them into
*************
clear*
set obs 100000
tempvar unif
gen `unif'=runiform()
gen byte x= /*
your x1 equals 3 here
*/ inrange(`unif',0,.4)*3+ /*
your x2 equals 7
*/ inrange(`unif',.4,.5)*7+ /*
your x3 equals 12
*/ inrange(`unif',.5,.8)*12+ /*
your x4 equals 19
*/ inrange(`unif',.8,.85)*19+ /*
your x4 equals 34
*/ inrange(`unif',.85,1)*34
ta x
*************
HTH
Martin
-----Ursprüngliche Nachricht-----
Von: [email protected]
[mailto:[email protected]] Im Auftrag von Dorothy Bridges
Gesendet: Montag, 5. Oktober 2009 14:56
An: [email protected]
Betreff: Re: st: AW: Randomly assigning values with a specific distribution
Thank you Martin!
On Mon, Oct 5, 2009 at 8:51 AM, Martin Weiss <[email protected]> wrote:
>
> <>
>
>
>
> *************
> clear*
> set obs 10000
>
> gen x=irecode(runiform(), 0, 0.4, /*
> */ 0.5, 0.8, .85)
>
> ta x
> *************
>
>
>
> HTH
> Martin
>
> -----Ursprüngliche Nachricht-----
> Von: [email protected]
> [mailto:[email protected]] Im Auftrag von Dorothy
Bridges
> Gesendet: Montag, 5. Oktober 2009 14:50
> An: [email protected]
> Betreff: st: Randomly assigning values with a specific distribution
>
> Dear Statalist:
>
> I would like to create a random variable taking five different values
> whose distribution mirrors that of another variable. In other words,
> I have one variable whose distribution is, say:
>
> value %
> x1 40
> x2 10
> x3 30
> x4 5
> x5 15
>
> ... and I want to create another variable with the same values and
> distribution, but randomly assigned. Something like gen randomvar =
> mydist() instead of uniform().
>
> Thanks,
> Dorothy
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