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Re: st: Standard normal Depvar
From 
 
Evans Jadotte <[email protected]> 
To 
 
[email protected] 
Subject 
 
Re: st: Standard normal Depvar 
Date 
 
Fri, 07 Aug 2009 09:00:54 +0200 
Nick Cox wrote:
To echo Austin Nichols, your assertion about exponentiation and change 
of rank is quite incorrect. Think of a plot of exp(x) and you will see 
that it is a monotonic function with any real as argument and so rank 
reversal will not occur.
Also, to expand on my earlier comment, only linear transforms will map 
normals to normals.
Nick
Evans Jadotte wrote:
> Thanks Nick. However, exponentiation will result in a re-ranking of
> individuals, which I must avoid. For instance, someone with a score -5
> compared with one whose score is 4, the former will end up being ranked
> higher than the latter after exponentiating. I need to preserve the
> ranks and normality after transforming.
Nick Cox wrote:
Exponentiation will get you all positives. After that many options 
are open.
Evans Jadotte wrote:
Nick Cox wrote:
This produces zero or positive values.
Less pedantically, if the variable is already standard normal, why 
does it need transforming?
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Hello Nick,
You did not read my earlier mail apologizing for my mind lapsus. I was 
thinking about squaring all variables when I mentioned the re-ranking 
issue. Evidently exponentiation preserves ranks. Also, as Austin 
mentioned that the exercise I want to carry out does not make sense, it 
has been applied many time in papers published from refereed journals 
and was proposed the time by: Amemiya (1977) The ML 
Estimator............ /Econometrica 45:955-68/. 
Many thanks again for the feedback.
Evans
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