hi
nicola orsini (from karolinska institute) provided me with this back in 2005 (i used (and still do) stata 8.2, should not make a difference if you are using stata 10):
// suppose you have 4 studies
clear
input study cases total
1 20 1000
2 40 5000
3 30 1500
4 25 3300
end
gen p = .
gen se = .
// get proportions and std errors
forv i =1(1)4 {
cii total[`i'] cases[`i']
qui replace p = r(mean) in `i'
qui replace se = r(se) in `i'
}
// get the inverse variance-weighted proportion
// use the official Stata -vwls- command
gen cons =1
vwls p cons, sd(se)
// use the user written -metan- command
// for fixed-effects meta-analysis
metan p se, nograph fixed
// for random-effects meta-analysis
metan p se, nograph random
hth,
bw
----------------------------------------
> Subject: st: meta-analysis question
> Date: Thu, 2 Jul 2009 12:11:50 -0400
> From: [email protected]
> To: [email protected]
>
> I am doing a meta-analysis in which I will need to generate pooled
> prevalence rates (e.g., prevalence of congenital heart disease in
> children presenting with a murmur). Metan seems to require 2 groups. I
> only have a single group. How do I do this? Thanks. Nader Shaikh
>
>
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