If your problem is just the leading zero issue, try:
replace date = "0" + date if length(date)==7
On Thu, Aug 28, 2008 at 7:12 AM, Michael McCulloch <[email protected]> wrote:
> *********
> On 8/23 I submitted a question: > I have dates in an Excel *.csv file as:
>>
>> date
>> 12/12/08
>> 12/02/08
>> 04/14/08
>> 04/04/08
>>
>> I wrote the following code to convert to Stata date:
>> gen str date_year = substr(date, -2,.)
>> gen str date_month = substr(date, 1, 2)
>> gen str date_day = substr(date, 4, 2)
>> destring date_year date_month date_day, replace
>> list date date_month date_day date_year
>>
>> However, when I import the *.csv file, the leading zeroes are dropped
>> from months 1-9.
>> Is there a way to solve this in Stata, without having to create
>> separate columns for m, d, and y in Excel?
>
> *********
> On 8/24 Salah responded with the following advice, which unfortunately is
> not successful (error msg: 60 missing values generated). I note that Salah's
> code which he wrote in Stata 10.1 worked for him, but not for me; I'm using
> 9.2. Any advice?
>
>
>
> Have you tried the date function?
>
> input str12 date
> "12/12/08"
> "12/02/08"
> "4/14/08"
> "4/04/08"
> end
> gen d=date(date, "MDY", 2010)
> format d %d
> list
>
> Tested using Stata 10.1
>
> *********
>
> *
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>
*
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