Liz's advice applies to Stata 9 (and back some). It does not apply to
Stata 10
(unless under version control):
. di date("31/12/94", "dm19y")
.
. version 9 : di date("31/12/94", "dm19y")
12783
Nick
[email protected]
Elizabeth Allred
gen datef = date(datestr, "dm19y")
Note d m and y are lower case. Upper case does NOT work.
Nuno
> I'm haing a problem with the date function when trying to convert a
string
> variable into a date variables. My string variable is datestr and
contains
> dates in the following format "31/12/94", ie, DMY. I've tried to use
the
> date function using the following syntax:
>
> gen datef = date(datestr, "DMY")
>
> I've already used this deffinition and it worked well, but the date
had the
> format "31/12/1994". Is there a way of using the date function with
the
> format I'm currently using, ie, with the last two digits in year?
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