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From |
"Scott Merryman" <[email protected]> |

To |
[email protected] |

Subject |
Re: st: RE: Re: Calculation of integrals |

Date |
Tue, 11 Dec 2007 13:50:45 -0600 |

```
I believe with Limdep, in this case, you need to restrict the sample
before Fintegrate command:
Sample ; 1$
Also, try a more basic example:
clear
set obs 100
range x 0 100
integ x x
Do the following Limdep commands (without restricting the sample) also
results in an integral 5000?
Fintegrate ;fcn = var
;labels = var
;start = 0
;pts =100
;limit = 0,100
;vary(var)
$
Scott
On Dec 11, 2007 12:24 PM, Mentzakis, Emmanouil <[email protected]> wrote:
> Dear Rodrigo,
>
> Thanks for your reply. Differences in the results are not restricted to
> a specific integral.
>
> E.g. using the command below
>
> clear
> range x 1 100 50
> g double lnx=ln(x)
> g double y=5*lnx
> integ y x, g(result)
>
> If I understand correctly, I compute the integral with lower limit 1 and
> upper limit 100, over 50 points and the function integrated is 5*ln(x).
> Is this correct?
>
> Similarly in Limdep, I thought that the same calculation would be done
> by the command
>
> Fintegrate ;fcn = 5*log(var)
> ;labels = var
> ;start = 10
> ;pts =50
> ;limit = 1,100
> ;vary(var)
> $
>
> Where, again, the limits are from 1 to 100, for 50 points and for the
> function 5*log(x). What is specified as "start" does not influence the
> calculation. It, actually, is a value given so that it can be assessed
> before the computation is done whether the function evaluation is
> possible at all.
>
> I'd really appreciate if you could comment on the equality of the two
> commands, because probably I am estimating two different things without
> realising it.
>
> Thanks
> Manos
>
>
>
>
> -----Original Message-----
> From: [email protected]
> [mailto:[email protected]] On Behalf Of Rodrigo A.
> Alfaro
> Sent: 11 December 2007 00:47
> To: [email protected]
> Subject: st: Re: Calculation of integrals
>
> Manos,
>
> It is difficult to give an answer with this info. What is exactly the
> integral that you want to calculate? What is the initial parameter in
> Limdep? It seems that you are trying to get an integral of the normal
> cdf, then something like 1000 seems too much as result (just a guess)
>
> Rodrigo.
>
>
> ----- Original Message -----
> From: "Mentzakis, Emmanouil" <[email protected]>
> To: <[email protected]>
> Sent: Monday, December 10, 2007 4:47 PM
> Subject: st: Calculation of integrals
>
>
> > Dear all,
> >
> > I am calculating an integral in Stata and then compare the calculation
> > with the same calculation in Limdep.
> >
> > However, the difference between the two calculations is very big
> (Stata
> > = 3.233 ; Limdep = 980.525).
> >
> > Below I have the code for Stata and the code for Limdep.
> >
> > Could anyone explain if I am making a mistake or what is the reason
> for
> > this result?
> >
> > Thank you
> > Manos
> >
> >
> > *****************************
> > *********** Stata ***********
> > *****************************
> >
> > clear
> > set obs 300
> > capture drop xb x
> > g xb=invnormal(uniform())
> > range x .001 1000 300
> > g double lnx=ln(x)
> > g double norm=normal(xb + .5*lnx)/300
> > integ norm x, g(integral)
> >
> > number of points = 300
> >
> > integral = 3.233067
> >
> >
> >
> > ********************************
> > ************ Limdep ************
> > ********************************
> > Coping the data from Stata, in Limdep we don't have to create a
> variable
> > for the range. It automatically uses the variable that is put in the
> > "label" and its limit is given by the "limit" and the number of points
> > by "pts". "Start" is the values of the parameters, but changing it
> > doesn't make any difference in the actual calculation.
> >
> > Fintegrate ;fcn = PHI(xb + .5*log(var))/300
> > ;labels = var
> > ;start = 500
> > ;pts =300
> > ;limit = 0.001,1000
> > ;vary(var)
> > $
> > +---------------------------------------------------+
> > | Function integration: |
> > | Grid is 300 points in [ .001 to 1000.000] |
> > | Value of the integral is 980.52567 |
> > +---------------------------------------------------+
> >
> >
> >
> >
> > *
> > * For searches and help try:
> > * http://www.stata.com/support/faqs/res/findit.html
> > * http://www.stata.com/support/statalist/faq
> > * http://www.ats.ucla.edu/stat/stata/
>
> *
> * For searches and help try:
> * http://www.stata.com/support/faqs/res/findit.html
> * http://www.stata.com/support/statalist/faq
> * http://www.ats.ucla.edu/stat/stata/
>
> *
> * For searches and help try:
> * http://www.stata.com/support/faqs/res/findit.html
> * http://www.stata.com/support/statalist/faq
> * http://www.ats.ucla.edu/stat/stata/
>
*
* For searches and help try:
* http://www.stata.com/support/faqs/res/findit.html
* http://www.stata.com/support/statalist/faq
* http://www.ats.ucla.edu/stat/stata/
```

**References**:**st: RE: Re: Calculation of integrals***From:*"Mentzakis, Emmanouil" <[email protected]>

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