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# st: Re: summing up digits and comparing to a check digit

 From "Michael Blasnik" To Subject st: Re: summing up digits and comparing to a check digit Date Wed, 15 Mar 2006 10:21:51 -0500

I'm not sure I understand the problem -- one of your examples is an 8 digit number but you say you have 7 digit numbers. Anyway, here is some "highly advanced programming" (?) :

gen x=string(myvar)
replace x="0"+x if length(x)==6
gen check=mod(real(substr(x,2,1))+real(substr(x,3,1))+real(substr(x,4,1))+real(substr(x,5,1))+real(substr(x,6,1))+real(substr(x,7,1)),10)

make sure to remove any line break that the email puts in the last line.

Michael Blasnik

----- Original Message ----- From: "Lia Orfei" <lorfei@sgul.ac.uk>
To: <statalist@hsphsun2.harvard.edu>
Sent: Wednesday, March 15, 2006 9:54 AM
Subject: st: summing up digits and comparing to a check digit

Dear all,
Here is a highly advanced programming challenge for you (!)

I have a variable that contains 7-digit numbers; the first digit is the remainder of the sum of the last six digits divided by 10 (check digit)

example: 1030332 => 0+3+0+3+3+2=11/10=1+1 => check digit=1
12050457 => 0+5+0+4+5+7=21/10=2+1 => check digit=1
and so on.

Now I want to assess whther the check digit is correct for each entry.

How do I calculate the partial sum of the contents of this variable?

Extra challenge: some of the numbers sum up to 10, 20 etc so the check digit is actually 0 and it does not appear in the data for some reason (example 50456 is correct becasue 5+0+4+5+6=20 so the remainder is 0).

Any ideas?? I was thinking about using the string functions.

Thanks a lot

Lia
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