The "V" is there because I am an idiot :) and tried to do two things
at once. Thanks for taking time to help.
scott
p.s. thanks as well for all of your effort with this list, I have
learned a lot from you in the last couple of years.
On 9/13/05, Nick Cox <[email protected]> wrote:
> "76(4|5).3"
>
> and
>
> "^76(4|5).3"
>
> both seem to work here. What's that "V" doing?
>
> Nick
> [email protected]
>
> scott hankins
>
> > I am trying to use the new regex functions and am having some issues.
> >
> > I am familiar (but not an expert) with regular expressions in Perl and
> > I am problems applying that knowledge in Stata. Does anyone know how
> > regular expressions are implemented in Stata? Ideally, I would like
> > more than "Regular expression syntax is based on Henry Spencer's NFA
> > algorithm and as such, is nearly identical to the POSIX.2 standard."
> > as I have not been able to find a clear exposition of the POSIX.2
> > standard online (I am sure there is one, I just can't find it :) ).
> >
> >
> > ***********************************
> > here is my problem
> >
> > pdx
> > 76403
> > 76403
> > 76513
> > 76503
> >
> >
> > I tried the following code but it did not find any matches, this
> > should find all 4 of the above occurrences.
> >
> > replace weight = 3 if regexm(pdx,"V76(4|5).3")
>
> *
> * For searches and help try:
> * http://www.stata.com/support/faqs/res/findit.html
> * http://www.stata.com/support/statalist/faq
> * http://www.ats.ucla.edu/stat/stata/
>
*
* For searches and help try:
* http://www.stata.com/support/faqs/res/findit.html
* http://www.stata.com/support/statalist/faq
* http://www.ats.ucla.edu/stat/stata/
