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From |
[email protected] (William Gould, Stata) |

To |
[email protected] |

Subject |
Re: st: average value among differing numbers of variables |

Date |
Thu, 17 Jul 2003 09:13:36 -0500 |

Radu Ban <[email protected]> writes, > This is a data management question. The data that I'm looking at (daily U.S. > weather) has the following structure. > > day1 flag1 day2 flag2 day3 flag3 day4 flag4 day5 flag5 ... day31 flag31 > 0 s a2 a 0 s 0 s a5 a a31 > 0 s 0 s b3 a b4 b5 b31 > c1 0 s 0 s 0 s c5 a c31 > > the "s" flag means that the measured element (say inches of rain) is > accumulated over those days, which are assigned a 0 value, and the > accumulated amount is reported in the day flagged with "a". i would like to > replace the 0 value for the accumulation days with the average of the > accumulated value over those days. > > given the notations above, specifically, i would like to replace 0, 0, b3 > (in the second row) with b3/3; 0, 0, 0, c5 (in the third row) with c5/4, and > so on. note that, as in the first row there can be more than one > accumulation series per row. I do now know what the solution to this problem is yet -- I will -- but I do know these kinds of problems are easier viewed the long way: orig_obs i day flag 1 1 0 s 1 2 a2 a 1 3 0 s 1 4 0 s 1 5 a5 a ... 1 31 a31 2 1 0 s 2 2 0 s 2 3 b3 a 2 4 0 s 2 5 c5 a ... 2 31 c31 etc. -reshape- can make the data look like that -- we'll worry about the details later. I am unsure from Radu's description whether variable flag ever contains anything on that "a" and "s". Radu sort of implies " " is also possible, in which case the measurement would be for that day. If so, I could view that as an "a" observation: One accumulates the single day and divides by one. So just in case there are any blanks, . replace flag = "a" if flag=="s" and then, just to verify that these data are as they have been explained to be, let's verify that flag is now always "s" or "a": . assert flag=="s" | flag=="a" Now the problem is getting easier: 1. We start accumulation at the first observation for each orig_obs group. 2. We continue accumulation up until we see an "a". 3. Then, we start accumulation again. So let's add a new variable begin that will record 1 every time an accumulation begins: . by orig_obs: gen begin = cond(_n==1 | flag[_n-1]=="a", 1, 0) Now our dataset looks like, orig_obs i day flag begin 1 1 0 s 1 1 2 a2 a 0 1 3 0 s 1 1 4 0 s 0 1 5 a5 a 0 ... 1 31 a31 a <could be 0 or 1> 2 1 0 s 1 2 2 0 s 0 2 3 b3 a 0 2 4 0 s 1 2 5 c5 a 0 ... 2 31 c31 a <could be 0 or 1> Understand what I did: I merely created a variable equal to 1 marking the beginning of each group in which we need to distribute sum. If I now sum variable begin, I will have group numbers: . gen group = sum(begin) The data set now looks like: orig_obs i day flag begin group 1 1 0 s 1 1 1 2 a2 a 0 1 1 3 0 s 1 2 1 4 0 s 0 2 1 5 a5 a 0 2 ... 1 31 a31 a ? 10 <- i just made up 10 2 1 0 s 1 11 2 2 0 s 0 11 2 3 b3 a 0 11 2 4 0 s 1 12 2 5 c5 a 0 12 ... 2 31 c31 a ? ? etc. Now the problem is easy: within group, replace all the observations with the value of the last observation in the group, divided by the number of observations in the group: . sort group . by group: gen newday = day[_N]/_N I have my solution. Actually, I could have typed . by group: replace day = day[N]/_N but I want to -list- the result and make sure it looks right to me. Then I can replace day: . replace day = newday . drop newday Now all I need to do is switch the data back to being in the wide format. So here is the complete solution: . gen orig_obs = _n . reshape long day flag, i(i) . replace flag = "a" if flag=="s" . assert flag=="s" | flag=="a" . sort orig_obs i . by orig_obs: gen begin = cond(_n==1 | flag[_n-1]=="a", 1, 0) . gen group = sum(begin) . sort group . by group: gen newday = day[_N]/_N . list <-- look to make sure right . replace day = newday . drop newday group . reshape wide -- Bill [email protected] * * For searches and help try: * http://www.stata.com/support/faqs/res/findit.html * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

**Follow-Ups**:**Re: st: average value among...(long)***From:*Radu Ban <[email protected]>

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