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Re: st: theory reg vs. qreg


From   Kasal Roman <kasalroman@gmail.com>
To   statalist@hsphsun2.harvard.edu
Subject   Re: st: theory reg vs. qreg
Date   Mon, 29 Apr 2013 13:17:07 +0200

of course I don't mean this, I know a2!=mean(x) but IF you put
a2=mean(x) you get the first method result with the "reg" command :)

On Mon, Apr 29, 2013 at 12:39 PM, Nick Cox <njcoxstata@gmail.com> wrote:
>
> What you want is not at all clear. In fact, you seem confused about some basics.
>
>  For example, if you fit a regression
>
> Y2=a2*x+b2
>
> it's not true that a2 = mean(x).
>
> What do you mean by "deactivate" a coefficient?
>
> -qreg y-
>
> works; it's just a round-about way of calculating the median of -y-,
> which you can do directly with -summarize-.
>
> Nick
> njcoxstata@gmail.com
>
>
> On 29 April 2013 11:23, Kasal Roman <kasalroman@gmail.com> wrote:
> > Please,
> >
> >
> > the "reg" command gives me these results:
> >
> > A) Y1=b1
> >
> > B) Y2=a2*x+b2
> >
> > then
> >
> > Y2=mean(x)*x+b2=b1=Y1
> >
> >
> > How is it with "qreg"? How could I deactivate the "a2" coefficient
> > without a need to estimate two functions with the "qreg" command? How
> > to get the result of "b1" just with the B) method through the "qreg"
> > command? I know neither mean(x) nor median(x) fit.
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