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Re: st: theory reg vs. qreg


From   Nick Cox <njcoxstata@gmail.com>
To   "statalist@hsphsun2.harvard.edu" <statalist@hsphsun2.harvard.edu>
Subject   Re: st: theory reg vs. qreg
Date   Mon, 29 Apr 2013 11:39:32 +0100

What you want is not at all clear. In fact, you seem confused about some basics.

 For example, if you fit a regression

Y2=a2*x+b2

it's not true that a2 = mean(x).

What do you mean by "deactivate" a coefficient?

-qreg y-

works; it's just a round-about way of calculating the median of -y-,
which you can do directly with -summarize-.

Nick
njcoxstata@gmail.com


On 29 April 2013 11:23, Kasal Roman <kasalroman@gmail.com> wrote:
> Please,
>
>
> the "reg" command gives me these results:
>
> A) Y1=b1
>
> B) Y2=a2*x+b2
>
> then
>
> Y2=mean(x)*x+b2=b1=Y1
>
>
> How is it with "qreg"? How could I deactivate the "a2" coefficient
> without a need to estimate two functions with the "qreg" command? How
> to get the result of "b1" just with the B) method through the "qreg"
> command? I know neither mean(x) nor median(x) fit.
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