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From |
Leonardo Jaime Gonzalez Allende <leonardo.gonzalez@ine.cl> |

To |
"statalist@hsphsun2.harvard.edu" <statalist@hsphsun2.harvard.edu> |

Subject |
RE: st: Quintiles |

Date |
Wed, 8 Aug 2012 15:44:57 -0400 |

Yes, Maarten, you are right, sorry for writing you directly. I don't was planning to cut a person or household in many parts. The question was about a possible adjustment to the weight factor, if the observation of the sample is the cut point of the quintile. If I sort the households of a sample by their incomes, a household "x" could represents 300 households but the accumulated frequency of the population is e.g. 20,02%. My question was if there is an efficient way (command) to repeat the observation and adjust weight factor as follow: the same household "xa" now represents 280 households and now the accumulated frequency of the population is e.g. 20% (exactly) (leaving to the first quintile). the same household "xb" (the other part) represents 20 households accumulating a frequency of 20,02% of the population (changing to the second quintile this part). Regards, Leonardo -----Mensaje original----- De: Maarten Buis [mailto:maartenlbuis@gmail.com] Enviado el: Miércoles, 08 de Agosto de 2012 12:41 Para: statalist@hsphsun2.harvard.edu Asunto: Re: st: Quintiles --- Leonardo Jaime Gonzalez Allende asked: >>> I'm trying to divide a sample of households (expanded) >>> into quintiles using the xtile command. I want to create >>> 5 groups with the exactly same quantity of population, >>> but using the xtitle command, the quantity of households >>> in each quintil is very slightly different to 20% when the >>> number of observations isn't exactly dividable by 5. >>> Do you know any command to divide the population >>> (sample expanded) into 5 groups of exactly same weight? --- I answered: >> That is logically impossible. -- Leonardo Jaime Gonzalez Allende wrote me privately: > sorry for write you directly, but I like to know, why is > logically impossible separate the population (by > incomes) in 5 groups of the same weith? Don't sent such follow-up questions privately. If you find my answer puzzling, than chances are that someone else who is following this discussion finds that too. This is explained in the Statalist FAQ. Think of it this way: How can you divide 6 persons in 5 equally sized groups? You could assign one person to each group, and than you are left with one person. If you could split the remaining 1 person up into 5 1/5th persons, than we could create 5 equally sized groups. However, that is impossible (or rather bloody, if we take that too literally). So given the inherently discrete nature of the number of observations you cannot divide your data up into 5 groups of exactly the same size if the number of observations in not dividable by 5. -- Maarten --------------------------------- Maarten L. Buis WZB Reichpietschufer 50 10785 Berlin Germany http://www.maartenbuis.nl --------------------------------- * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

**Follow-Ups**:**Re: st: Quintiles***From:*Austin Nichols <austinnichols@gmail.com>

**Re: st: Quintiles***From:*Maarten Buis <maartenlbuis@gmail.com>

**References**:**st: One Step and 2 step GMM***From:*muneer <mkmmuneerbabu@gmail.com>

**st: xtreg check for outliers***From:*Dalhia <ggs_da@yahoo.com>

**st: RE: xtreg check for outliers***From:*"Jacobs, David" <jacobs.184@sociology.osu.edu>

**st: Quintiles***From:*Leonardo Jaime Gonzalez Allende <leonardo.gonzalez@ine.cl>

**Re: st: Quintiles***From:*Maarten Buis <maartenlbuis@gmail.com>

**Re: st: Quintiles***From:*Maarten Buis <maartenlbuis@gmail.com>

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