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Re: st: Clustering with Sequence analysis/optimal matching


From   Ulrich Kohler <kohler@wzb.eu>
To   statalist@hsphsun2.harvard.edu
Subject   Re: st: Clustering with Sequence analysis/optimal matching
Date   Wed, 21 Mar 2012 12:08:55 +0100

Stefan,

the problem that you are reporting typcially happens with the version of
the program that was distributed togehter with the cited SJ article.
There is a newer version of the program available on SSC. Please use

. ado uninstall st0111 
. ssc install sq

to update to the most recent version of the package. 

Note as an aside that the most recent version of the sq-package also has
a lot of new features, including further functions for -egen-, a way to
apply multidimensional scaling to the distance matrix, decreased
overplotting of lines in sequence index plots, and a new graphical
device for plotting "ideal typical" sequences (-sqmodalplot-). 

Many regards

Uli



Am Mittwoch, den 21.03.2012, 11:38 +0100 schrieb Stefan Weih:
> Dear Statalist-members,
> 
> I am currently analyzing diversification strategy sequences with 16
> potential sequence states using the sqom (optimal matching) command.
> As a common next step I would like to cluster my sqom-results. For this, I
> am using the command sqclusterdat procedure as described in “Sequence
> analysis with Stata” (Brzinsky-Fay/Kohler/Luniak, 2006, The Stata
> Journal6(4), 435-460). The syntax I am using looks the following:
> 
> sqset Seq ID Order
> 
> sqom, subcost(matrixA) full
> 
> sqclusterdat
> clustermat wardslinkage SQdist, name(wards) add
> sqclusterdat, return
> 
> However, the clustering does not work properly. After performing
> sqclusterdat, return I keep receiving the following message “Group results
> could not be merged to sequence data. Returned to original sequence data”.
> 
> Unfortunately the cause for this message is not obvious to me. I am
> thankful for any guidance and hints that can help me out.
> 
> Sincerely,
> Stefan Weih
> 
> 
> The data looks like:
> 
> ID	Seq	Order
> 41	11	1
> 41	13	2
> 41	11	3
> 41	21	4
> 42	11	1
> 42	13	2
> 42	12	3
> 42	11	4
> 43	14	1
> 43	13	2
> 43	11	3
> 43	12	4
> 
> 
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