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From |
Daniel Mueller <mueller@iamo.de> |

To |
statalist@hsphsun2.harvard.edu |

Subject |
Re: st: RE: How to define shortest possible period with 95% of observations |

Date |
Wed, 12 May 2010 21:59:25 +0700 |

Thanks a lot in advance and best regards, Daniel *** start forv y = `yearfirst'/`yearlast' { * keep previous year if `y' != `yearfirst' { keep if Year == `y' | Year == (`y'-1) } bys Day: g no_fire_day = _N qui su no_fire_day * define year to start 183 days before peak fire day loc yearstart = Day[r(max)] - 183 loc yearend = `yearstart' + 365 keep if Day > `yearstart' & Day < `yearend' // or with egen->rotate? bys Day: keep if _n == _N g nobs = _n * the target is a continuous run that includes 95% of all fires sum no_fire_day, meanonly scalar target = .95 * r(sum) scalar shortlen = . gen arun = . gen bestrun = . * at each pass, create a run that starts at nobs == `i' * and identify the nobs where the number of fires >= 95% local more 1 local i = 0 while `more' { local i = `i' + 1 qui replace arun = sum(no_fire_day * (nobs >= `i')) sum nobs if arun >= target, meanonly if r(N) == 0 local more 0 else if (Day[r(min)] - Day[`i']) < shortlen { scalar shortlen = Day[r(min)] - Day[`i'] qui replace bestrun = arun qui replace bestrun = . if nobs > r(min) | nobs < `i' } } qui drop if bestrun == . drop bestrun arun save fires_`y', replace } *** end Robert Picard wrote on 5/11/2010 3:28 AM:

Here is how I would approach this problem. I would do each year separately; it could be done all at once but it would complicate the code unnecessarily. If the fire data is one observation per fire, I would -collapse- it to one observation per day. Each observation would contain the number of fires that day. The following code will identify the first instance of the shortest run of days that includes 95% of fires for the year. Note that the following code will work, even if there are days without fires (and thus no observation for that day). *--------------------------- begin example ----------------------- version 11 * daily fire counts; with some days without fires clear all set seed 123 set obs 365 gen day = _n drop if uniform()< .1 gen nobs = _n gen nfires = round(uniform() * 10) * the target is a continuous run that includes 95% of all fires sum nfires, meanonly scalar target = .95 * r(sum) dis target scalar shortlen = . gen arun = . gen bestrun = . * at each pass, create a run that starts at nobs == `i' * and identify the nobs where the number of fires>= 95% local more 1 local i 0 while `more' { local i = `i' + 1 qui replace arun = sum(nfires * (nobs>=`i')) sum nobs if arun>= target, meanonly if r(N) == 0 local more 0 else if (day[r(min)] - day[`i'])< shortlen { scalar shortlen = day[r(min)] - day[`i'] qui replace bestrun = arun qui replace bestrun = . if nobs> r(min) | nobs< `i' } } *--------------------- end example -------------------------- Hope this help, Robert On Mon, May 10, 2010 at 6:19 AM, Nick Cox<n.j.cox@durham.ac.uk> wrote:I don't think any trick is possible unless you know in advance the precise distribution, e.g. that it is Gaussian, or exponential, or whatever, which here is not the case. So, you need to look at all the possibilities from the interval starting at the minimum to the interval starting at the 5% point of the fire number distribution in each year. However, this may all be achievable using -shorth- (SSC). Look at the -proportion()- option, but you would need to -expand- first to get a separate observation for each fire. If that's not practicable, look inside the code of -shorth- to get ideas on how to proceed. Note that no looping is necessary: the whole problem will reduce to use of -by:- and subscripts. Nick n.j.cox@durham.ac.uk Daniel Mueller I have a strongly unbalanced panel with 100,000 observations (=fire occurrences per day) that contain between none (no fire) and 3,000 fires per day for 8 years. The fire events peak in March and April with about 85-90% of the yearly total. My question is how I can define the shortest possible continuous period of days for each year that contains 95% of all yearly fires. The length and width of the periods may slightly differ across the years due to climate and other parameters. I am sure there is a neat trick in Stata for this, yet I have not spotted it. Any suggestions would be appreciated. * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/* * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

* * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

**Follow-Ups**:**RE: st: RE: How to define shortest possible period with 95% of observations***From:*"Nick Cox" <n.j.cox@durham.ac.uk>

**Re: st: RE: How to define shortest possible period with 95% of observations***From:*Steve Samuels <sjsamuels@gmail.com>

**References**:**st: How to define shortest possible period with 95% of observations***From:*Daniel Mueller <mueller@iamo.de>

**st: RE: How to define shortest possible period with 95% of observations***From:*"Nick Cox" <n.j.cox@durham.ac.uk>

**Re: st: RE: How to define shortest possible period with 95% of observations***From:*Robert Picard <picard@netbox.com>

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