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From |
"Nick Cox" <n.j.cox@durham.ac.uk> |

To |
<statalist@hsphsun2.harvard.edu> |

Subject |
st: RE: How to define shortest possible period with 95% of observations |

Date |
Mon, 10 May 2010 11:19:29 +0100 |

I don't think any trick is possible unless you know in advance the precise distribution, e.g. that it is Gaussian, or exponential, or whatever, which here is not the case. So, you need to look at all the possibilities from the interval starting at the minimum to the interval starting at the 5% point of the fire number distribution in each year. However, this may all be achievable using -shorth- (SSC). Look at the -proportion()- option, but you would need to -expand- first to get a separate observation for each fire. If that's not practicable, look inside the code of -shorth- to get ideas on how to proceed. Note that no looping is necessary: the whole problem will reduce to use of -by:- and subscripts. Nick n.j.cox@durham.ac.uk Daniel Mueller I have a strongly unbalanced panel with 100,000 observations (=fire occurrences per day) that contain between none (no fire) and 3,000 fires per day for 8 years. The fire events peak in March and April with about 85-90% of the yearly total. My question is how I can define the shortest possible continuous period of days for each year that contains 95% of all yearly fires. The length and width of the periods may slightly differ across the years due to climate and other parameters. I am sure there is a neat trick in Stata for this, yet I have not spotted it. Any suggestions would be appreciated. * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

**Follow-Ups**:**Re: st: RE: How to define shortest possible period with 95% of observations***From:*Robert Picard <picard@netbox.com>

**References**:**st: How to define shortest possible period with 95% of observations***From:*Daniel Mueller <mueller@iamo.de>

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