[Date Prev][Date Next][Thread Prev][Thread Next][Date index][Thread index]

From |
Ronan Conroy <rconroy@rcsi.ie> |

To |
"statalist@hsphsun2.harvard.edu" <statalist@hsphsun2.harvard.edu> |

Subject |
Re: st: per standard deviation change |

Date |
Thu, 11 Sep 2008 13:07:48 +0100 |

On 11 Sep 2008, at 12:35, Mohammed El Faramawi wrote:

I want to ask about modeling a continuous variable as per standard deviation change. For example if I have a continuous variable such as arterial blood pressure(BP) measured in mmhg and I want to express the relationship between per standard deviation change of blood pressure and the physical activity (coded yes, no). How can I do that? Should I calculate the mean of BP abd then subtract it from the individual observation then divide the product by standard deviation.You are making life too complicated! Here's an example with mean arterial pressure, measured in women, late in pregnancy:

. regress map smoking if visit==5

Source | SS df MS Number of obs = 256

-------------+------------------------------ F( 1, 254) = 8.35

Model | 788.039627 1 788.039627 Prob > F = 0.0042

Residual | 23975.3197 254 94.3910226 R-squared = 0.0318

-------------+------------------------------ Adj R-squared = 0.0280

Total | 24763.3594 255 97.1112132 Root MSE = 9.7155

------------------------------------------------------------------------------

map | Coef. Std. Err. t P>|t| [95% Conf. Interval]

------------- +----------------------------------------------------------------

smoking | -3.562013 1.232783 -2.89 0.004 -5.989791 -1.134234

_cons | 93.37333 .7932676 117.71 0.000 91.81111 94.93555

------------------------------------------------------------------------------

You can see that smoking reduces the mean arterial pressure by 3.6 mm/ Hg (the coefficient for smoking) with a confidence interval of 1.1 to 6.0 (5.989791 rounded). This is an important reason why smokers' babies are born lighter than non-smokers' (they lose the equivalent to one week of gestational development).

Reporting the effect thus has the advantage that a clinician can understand it, because it is expressed in the units in which blood pressure is measured. And from your point of view, the advantage is that you can extract this information very easily from -regress-.

You can do likewise with your exercisers versus non-exercisers comparison.

No-one understands standard deviations in clinical medicine.

You will notice how I reported the effect size and its confidence interval with the minus signs removed. As a general rule, no-one understands negative numbers and no-one understands risk ratios or odds ratios that are less than one.

Or should I subtract the standard deviation from the individual observation?

Also, Should I take the absolute variable when the new variable is created or should I keep the signs when the regression is conducted?

Ronan Conroy

=================================

rconroy@rcsi.ie

Royal College of Surgeons in Ireland

Epidemiology Department,

Beaux Lane House, Dublin 2, Ireland

+353 (0)1 402 2431

+353 (0)87 799 97 95

+353 (0)1 402 2764 (Fax - remember them?)

http://www.flickr.com/photos/ronanconroy/sets/72157601895416740/

P Before printing, think about the environment

*

* For searches and help try:

* http://www.stata.com/help.cgi?search

* http://www.stata.com/support/statalist/faq

* http://www.ats.ucla.edu/stat/stata/

**Follow-Ups**:**RE: st: per standard deviation change***From:*"Martin Weiss" <martin.weiss@uni-tuebingen.de>

**References**:**st: per standard deviation change***From:*Mohammed El Faramawi <melfaram@yahoo.com>

- Prev by Date:
**st: Use -command- references, not --command references, please** - Next by Date:
**Re: st: Automatically generate table with t-stat for differences in means** - Previous by thread:
**st: RE: per standard deviation change** - Next by thread:
**RE: st: per standard deviation change** - Index(es):

© Copyright 1996–2016 StataCorp LP | Terms of use | Privacy | Contact us | What's new | Site index |