Re: st: Problems with program

[Christian Holz <statalist@krueschan.de>]

Andrea,
you'd have to define the -syntax- of you program after the -program 
define- line.
You'd tell Stata how the syntax of your program -regse- should look like 
 and to which variables the option should be parsed. The help of 
-syntax- should make it pretty clear.
Christian.
---
Christian Holz
Department of Sociology
University of Glasgow
Scotland, U.K.


Andrea Molinari wrote:

> Many thanks for all your replies!
> Nick, you're totally right. The main problem is that I can't put the program
> inside the loop because the word -end- stops the loop.
> I'm sorry for my ignorance, but can I please ask what did you mean by "pass
> `var' to -regse- in an option"? I thought this meant to define the local in
> the program, but that didn't work either.
> Many thanks again and again!
> Andrea
>
>
> ----- Original Message ----- 
> From: "n j cox" <n.j.cox@durham.ac.uk>
> To: <statalist@hsphsun2.harvard.edu>
> Sent: Thursday, August 18, 2005 5:17 PM
> Subject: Re: st: Problems with program
>
>
>
>
> > If I understand this correctly, this has nothing to do with -outreg-,
> > -estout- or any other program downstream. The problems are within your
> > own code.
> >
> > You refer to `var' within your program -regse- without ever defining it
> > previously in the same program. This is not illegal but Stata will
> > interpret the reference to a non-existent macro as an empty string and
> > the result will presumably not be what you want.
> >
> > That is, `var' within program -regse- is a local macro
> > name. The fact that the -foreach- loop outside your
> > program also uses a local macro name `var' has no implications
> > within your program. The two are in completely different
> > name spaces. That is precisely what the "local" of "local
> > macro" means.
> >
> > One possibility is to pass `var' to -regse- in an option.
> >
> > Nick
> > n.j.cox@durham.ac.uk
> >
> >
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