Philipp,
thanks for your explanation.
I think I overestimated what -encode- is actually doing, the explanation
under help -encode- is a bit short I find.
- Tom
-----Urspr=FCngliche Nachricht-----
Von: [email protected]
[mailto:[email protected]] Im Auftrag von Philipp Rehm
Gesendet: Donnerstag, 23. November 2006 13:48
An: [email protected]
Betreff: Re: st: "Wrong" result with encode / merge ?
Assume you have these id7temp codes in your master data-set:
AT18679
AT18680
AT18681
Assume you have these id7temp codes in your using data-set:
AT18679
AT18681
AT18682
If you -encode- the id7temp variable in each data-set, you will get the
following id7 variables:
In the master data-set:
1=3DAT18679
2=3DAT18680
3=3DAT18681
In the using data-set:
1=3DAT18679
2=3DAT18681
3=3DAT18682
That is, encodes simply assigns numbers to each string.
If you -merge- the using data-set with the master data-set on id7, you
will get the following (wrong) match:
1 "AT18679" =3D 1 "AT18679"
2 "AT18680" =3D 2 "AT18681"
3 "AT18681" =3D 3 "AT18682"
That's not what you want. I don't think that you should -encode- your
values. Simply -merge- on id7temp, not id7.
HTH,
Philipp
Thomas Erdmann wrote:
> Hi,
>
> I have a dataset with ids that look like: AT18679U (two strings followed
by
> 5 numbers, optionally followed by another string)
>
> Between the two datasets I would like to merge only the first 7 digits ar=
e
> equal, therefore I generated
>
> generate id7temp=3Dsubstr(id,1,7)
> encode id7temp, gen(id7)
> sort id7
>
> and merged the two datasets by id7. When I quality checked the results
there
> were several mismatches, which don't seem to happen if I use the string i=
d
> and not the encoded one. Why is that?
>
> Thanks in advance
> -Tom
>
>
>
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