# st: =?utf-8?B?UkU6IFJFOiBSRTogUkU6IFJFOiBSRTogUkU6IFJFOiA=?==?utf-8?B?c3Q6IMK0w7DCuMK0OiBzdDogSG93IHRvIGNob29zZSBhIHBy?==?utf-8?B?b3BlciBtb2RlbCBpZiB0aGUgZGVwZW5kZW50IHZhcmk=?==?utf-8?B?YWJsZSBpcyB3aXRoaW4gYm91bmRzPw==?=

 From "Nick Cox" To Subject st: =?utf-8?B?UkU6IFJFOiBSRTogUkU6IFJFOiBSRTogUkU6IFJFOiA=?==?utf-8?B?c3Q6IMK0w7DCuMK0OiBzdDogSG93IHRvIGNob29zZSBhIHBy?==?utf-8?B?b3BlciBtb2RlbCBpZiB0aGUgZGVwZW5kZW50IHZhcmk=?==?utf-8?B?YWJsZSBpcyB3aXRoaW4gYm91bmRzPw==?= Date Mon, 2 Oct 2006 15:00:59 +0100

```I don't think guessing is needed here, as this is basic
trigonometry, but yes,
vertical change = horizontal change X slope.

Nick
n.j.cox@durham.ac.uk

Cheng, Xiaoqiang

> Thank you very much.
>
> To make it clear, let's forget what I have said.
>
> What I want to know is, since dy/dx is the approximate slope
> and it should be explained as how much y will change respect
> to one unit change of x. In this case, I guess it will be
> right if we devide the value of the slope by 100 in order to
> know how much y will change respect to 1/100 unit change of x.
>

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