Re: st: RE: Generating skewed distributions on closed intervals

[Reza C Daniels <rdaniels@commerce.uct.ac.za>]

Hi Maarten,

I tried this in the following way:

set obs 100
-gen z1=invnorm(uniform())- where z>0
-gen z2=ln(z1)- for positively skewed
-gen z3=exp(z1)- for negatively skewed

As I'm sure you know, this gives me the correct shape of the 
distributions I'm looking for, but the incorrect range.

So, I still can't solve it.

Thanks anyway,
Reza


Maarten Buis wrote:

> It reminds me of an ordered probit problem: you have one unobserved distribution, which is being carved up. Only now you also have information about where the cuts are made. This should be solvable. You might want to look at the log normal instead of the normal though, since no one can get, or has ever been, -2 (even with plastic surgery).
>
>
>
> -----Original Message-----
> From: owner-statalist@hsphsun2.harvard.edu [mailto:owner-statalist@hsphsun2.harvard.edu]On Behalf Of Nick Cox
> Sent: donderdag 29 september 2005 11:09
> To: statalist@hsphsun2.harvard.edu
> Subject: RE: st: RE: Generating skewed distributions on closed intervals
>
> Well, I guess wildly the literature you are unaware of
> holds better solutions, but that's an empty comment
> as I don't know what it is. The idea that an age
> distribution is a bunch of little truncated
> Gaussians sitting next to each other on a line sounds
> at best strange to me, but as I said I don't
> understand what your problem is.
>
> Nick
> n.j.cox@durham.ac.uk
>
> Reza C Daniels
>
> > There is a literature on this problem that I am aware of. I'm just
> > having trouble with the code in Stata to generate my required results.
>
> > > Whatever your problem is, it is difficult to believe
> > > that there is not a literature on it, e.g. in demography,
> > > actuarial science, population ecology.
>
>
>
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