I. Mosca wrote:
we have an entry that looks like the following:
1-1-2002 00:00:00
It is a string variable str19 %19s.
We'd like to transform it into a numerical/date format, but the
information we want to keep is only the year.
How can we do that?
-----------
Looking at your date format it seems that the year precedes the first
blank in the string. I create two observations, identify the position of
the first blank character with strpos(), and use that in the substr()
function.
clear
input str19 datetime
"1-1-2002 00:00:00"
"10-12-1998 13:32:17"
end
gen x = strpos(datetime," ")
gen year = substr(datetime, x-4, 4)
In Stata 8 it is not strpos(), but index():
gen x = index(datetime," ")
Hope this helps
Svend
__________________________________________
Svend Juul
Institut for Folkesundhed, Afdeling for Epidemiologi
(Institute of Public Health, Department of Epidemiology)
Vennelyst Boulevard 6
DK-8000 Aarhus C, Denmark
Phone: +45 8942 6090
Home: +45 8693 7796
Email: [email protected]
__________________________________________
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