Yes, you're right, that solves half the problem. I've now switched the order
of the old and new variables. However, the 'if' command does not appear to
be working. How can I limit replacing of values to just those cases with a
specific value on a third variable? Thanks again for help,
Patrick
-----Original Message-----
From: [email protected]
[mailto:[email protected]]On Behalf Of Ernest
Berkhout
Sent: 28 May 2003 12:38
To: [email protected]
Subject: Re: st: RE: RE: looping through vectors
Patrick,
I think you're doing exactly the opposite of what you intended to do in the
3rd statement. You are copying the old values into the new ones (you
replace `new' with 'old')
At 13:12 28-5-2003, Patrick wrote:
>Nick
>
>thanks for your help. I'm running your second option for irregular suffixes
>and, although I don't seem to be getting error messages, it isn't working.
>The first vector comprises variables:
>
>rpy204 rpy203 rpy199 rpy206 rpy210 rpy202 rpy014 rpy207 rpy209 rpy013
rpy201
>rpy200 rpy018 rpy016 rpy017
>
>the second vector comprises:
>
>_rpy204 _rpy203 _rpy199 _rpy206_rpy210 _rpy202 _rpy014 _rpy207 _rpy209
>_rpy013 _rpy201 _rpy200 _rpy018 _ rpy016 _rpy017
>
>I have written the following code which produces the output as shown (note
>that I'm also including an if command as I only want to copy over values
>conditional on the value of additional variable). The values of the
>variables in the first vector (or set) remain uncyhanged when I tab them.
>Any ideas?
>
>Patrick
>
>. foreach v of var rpy* {
>2. local new : subinstr local v "rpy" "_rpy"
>3. replace `new' = `v'
>4. } if show3 == 1
Ernest Berkhout
SEO Amsterdam Economics
University of Amsterdam
Room 3.08
Roetersstraat 29
1018 WB Amsterdam
The Netherlands
tel.:+ 31 20 525 1657
fax:+ 31 20 525 1686
http://www.seo.nl
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