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Re: st: Arranging variables across rows
From
Nick Cox <[email protected]>
To
[email protected]
Subject
Re: st: Arranging variables across rows
Date
Wed, 27 Jun 2012 19:14:13 +0100
Yes, that sounds all too correct. My error. How about
drop D1-D19
forval i = 1/19 {
gen D`i' = 0
}
forval j = 1/19 {
forval k = 1/8 {
replace D`j' = 1 if A`j' == B`k' & B`k' < .
}
}
On Wed, Jun 27, 2012 at 7:07 PM, samuel gyetvay <[email protected]> wrote:
> Sorry, actually, the code is wrong in a different way: it creates a
> dummy variable equal to 1 if any B is equal to A along the same row.
> So in the case
>
> (A1) (A2) (A3) (A4) (B1) (B2) (B3) (B4)
> 101 102 103 104 . 101 . .
>
> you get D1, D2, D3, D4 all equal to 1
>
> -Sam
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