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From |
Nick Cox <njcoxstata@gmail.com> |

To |
statalist@hsphsun2.harvard.edu |

Subject |
Re: st: passing indefinite no of arguments |

Date |
Sat, 31 Mar 2012 17:47:55 +0100 |

Frankly, this is very confused. You need to keep separate macro manipulations and variable calculations. Also, thisn't really a problem that needs a program or a do-file at all. local myvars : var2 var3 unab all : var* local rest : list all - myvars egen rest_total = rowtotal(`rest') I advise trying simpler problems and studying the User's manual much more slowly and carefully. Nick On Sat, Mar 31, 2012 at 2:10 PM, tashi lama <ltashi32@hotmail.com> wrote: > That sounds great. Here is a slightly diff problem but with a similar flavor..Any idea? > > I have a dataset as follows > > var1 var2 var3 va4 var5 > > 4 5 6 3 3 > > I would like to enter variables as arugments and find the sum of the rest. Here is my attempt > > *sum of the selected vars > > tokenize `0' > > local length: word count `0' > > local varlist var* > > forvalues i=1/length { > > local var_new=varlist-`i' /* i am not so sure I can do this > replace varlist=`var_new' > drop var_new > } > > egen total=rowtotal(`varlist') > > so if I run, > > do filename var2 var3 , I expect to get the sum of var1 var4 and var5. > > I am thinkin I could also do sth like this, > > tokenize `0' > local length:word count `0' > > unab varlist:var* > > forvalues i=1/length { > > local var_new:list varlist- `i' > > } > > egen total=rowtotal(`var_new') > > Essentially I am trying to learn to subtract certain variables from the list of variables or a string. Any help will be highly appreciated... > > ---------------------------------------- >> Date: Sat, 31 Mar 2012 00:48:50 +0100 >> Subject: Re: st: passing indefinite no of arguments >> From: njcoxstata@gmail.com >> To: statalist@hsphsun2.harvard.edu >> >> di `: list sizeof 0 ' >> >> Nick >> >> On Fri, Mar 30, 2012 at 8:52 PM, Maarten Buis <maartenlbuis@gmail.com> wrote: >> > On Fri, Mar 30, 2012 at 8:43 PM, tashi lama wrote: >> >> So, say I have a do file which will add the arguments and display >> >> >> >> *sum >> >> >> >> args a b c d >> >> >> >> di `a' +`b'+`c'+`d' >> >> >> >> This one is easy since I could pass 4 arguments a! > , b, c and d and my do file will sum them. What if I don't know the no of arguments I am passing? I could have passed 2, 3, 5 or even 1 and find their sum. >> > >> > Here is a quick solution. The logic is that within a program a number >> > of locals are created. The local `0' contains all arguments, and the >> > local `1' contains the first argument, `2' the second, etc. This is >> > not very stable, e.g. when you call -tokenize- the locals `1', `2' >> > etc. will be replaced, but in a small program like the one below it is >> > an easy enough solution. >> > >> > *---------- begin example ------------ >> > program drop _all >> > program define sumargs >> > // count the number of arguments >> > local k : word count! > `0' >> > >> > // add them > > ; >> > tempname sum >> > scalar `sum' = 0 >> > forvalues i = 1/`k' { >> > scalar `sum' = `sum' + ``i'' >> > } >> > >> > // display the result >> > di `sum' >> > end >> > >> > sumargs 2 3 7 >> > sumargs 4 >> > sumargs 2 3 4 5 6 7 8 >> > *---------- end example ------------- >> > * * For searches and help try: * http://www.stata.com/help.cgi?search * http://www.stata.com/support/statalist/faq * http://www.ats.ucla.edu/stat/stata/

**Follow-Ups**:**RE: st: passing indefinite no of arguments***From:*tashi lama <ltashi32@hotmail.com>

**References**:**st: passing indefinite no of arguments***From:*tashi lama <ltashi32@hotmail.com>

**Re: st: passing indefinite no of arguments***From:*Maarten Buis <maartenlbuis@gmail.com>

**Re: st: passing indefinite no of arguments***From:*Nick Cox <njcoxstata@gmail.com>

**RE: st: passing indefinite no of arguments***From:*tashi lama <ltashi32@hotmail.com>

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