This question has already been answered.
http://www.stata.com/statalist/archive/2011-07/msg01072.html
On Sat, Jul 30, 2011 at 11:34 PM, Yusvita Triwiadhian S.
<07.5544@stis.ac.id> wrote:
> Dear Mr. Kleinbaum
>
> i'm running gompertz gamma frailty for survival analysis and get
> output like this :
>
> t haz.ratio std.error z P>|z| 95% CI
>
> /ln_the 2.04994 0.55177 3.72 0,000 0.96850 ; 3.13139
> theta 7.76747 4.28582
> 2.6340; 22.90569
>
> i want to ask about function of /ln_the ?? what is it means?
>
> then, if i want to know how many percent predictor variable can
> explain variation data of respon variable, (like R square if in linear
> regression), what must i do??
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