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Re: st: output survival analysis
From
Nick Cox <[email protected]>
To
[email protected]
Subject
Re: st: output survival analysis
Date
Fri, 29 Jul 2011 10:19:20 +0100
\ln_the means ln(theta) as you can verify for yourself.
. di ln(7.76747)
2.0499445
For "gompertz" read "Gompertz".
No doubt you can fudge an R^2 for yourself, but that is foisting
least-squares ideas where they are not central to the analysis:
FAQ . . . . . . . . . . . . . . . . . . . . . . . Do-it-yourself R-squared
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . N. J. Cox
9/03 How can I get an R-squared value when a Stata command
does not supply one?
http://www.stata.com/support/faqs/stat/rsquared.html
Nick
On Fri, Jul 29, 2011 at 9:28 AM, Yusvita Triwiadhian S.
<[email protected]> wrote:
> i'm running gompertz gamma frailty for survival analysis and get
> output like this :
>
> t haz.ratio std.error z P>|z| 95% CI
>
> /ln_the 2.04994 0.55177 3.72 0,000 0.96850 ; 3.13139
> theta 7.76747 4.28582 2.6340
> ; 22.90569
>
> i want to ask about function of /ln_the ?? what is it means?
>
> then, if i want to know how many percent predictor variable can
> explain variation data of respon variable, (like square R if in linear
> regression), what must i do??
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